What is 3x^2-12x-(y^2)/4-y/2+43/4 =0 ?

The solution to 3x^2-12x-(y^2)/4-y/2+43/4 =0 is Hyperbola with (h,k)=(2,-1),a=sqrt(1/3),b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3x^2-12x-(y^2)/4-y/2+43/4 =0

3 x^{2} - 12 x - \frac{y ^{2}}{4} - \frac{y}{2} + \frac{43}{4} = 0

(h, k) = (2, - 1), a = \frac{1}{3}, b = 2

Solution steps

3 x^{2} - 12 x - \frac{y ^{2}}{4} - \frac{y}{2} + \frac{43}{4} = 0

Rewrite

3 x^{2} - 12 x - \frac{y ^{2}}{4} - \frac{y}{2} + \frac{43}{4} = 0

in the form of a standard hyperbola equation

\frac{( x - 2 ) ^{2}}{( \frac{1}{3} ) ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, - 1), a = \frac{1}{3}, b = 2

- x^{2} + 3 y^{2} - 4 x + 6 y = 28

\frac{y ^{2}}{1} - \frac{x ^{2}}{15} = 1

\frac{( x - 2 ) ^{2}}{36} - \frac{( y + 1 ) ^{2}}{64} = 1

- x^{2} + y^{2} = - 13

- x^{2} + y^{2} = 51

What is 3x^2-12x-(y^2)/4-y/2+43/4 =0 ?
The solution to 3x^2-12x-(y^2)/4-y/2+43/4 =0 is Hyperbola with (h,k)=(2,-1),a=sqrt(1/3),b=2