What is ((x-1.6)^2)/4-((y+1)^2)/2 =1 ?

The solution to ((x-1.6)^2)/4-((y+1)^2)/2 =1 is Hyperbola with (h,k)=(1.6,-1),a=2,b=sqrt(2)

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((x-1.6)^2)/4-((y+1)^2)/2 =1

\frac{( x - 1.6 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{2} = 1

(h, k) = (1.6, - 1), a = 2, b = 2

Solution steps

\frac{( x - 1.6 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{2} = 1

Rewrite

\frac{( x - 1.6 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{2} = 1

in the form of a standard hyperbola equation

\frac{( x - 1.6 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{( 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1.6, - 1), a = 2, b = 2

\frac{( x - 4 ) ^{2}}{144} - \frac{( y - 11 ) ^{2}}{25} = 1

\frac{( x - 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

7 x^{2} - 5 y^{2} - 14 x + 40 y - 108 = 0

y^{2} - x^{2} = 25

36 (x - 5)^{2} - 64 (y - 2)^{2} = 2304

What is ((x-1.6)^2)/4-((y+1)^2)/2 =1 ?
The solution to ((x-1.6)^2)/4-((y+1)^2)/2 =1 is Hyperbola with (h,k)=(1.6,-1),a=2,b=sqrt(2)