What is ((x-3)^2)/6-((y-2)^2)/2 =1 ?

The solution to ((x-3)^2)/6-((y-2)^2)/2 =1 is Hyperbola with (h,k)=(3,2),a=sqrt(6),b=sqrt(2)

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((x-3)^2)/6-((y-2)^2)/2 =1

\frac{( x - 3 ) ^{2}}{6} - \frac{( y - 2 ) ^{2}}{2} = 1

(h, k) = (3, 2), a = 6, b = 2

Solution steps

\frac{( x - 3 ) ^{2}}{6} - \frac{( y - 2 ) ^{2}}{2} = 1

Rewrite

\frac{( x - 3 ) ^{2}}{6} - \frac{( y - 2 ) ^{2}}{2} = 1

in the form of a standard hyperbola equation

\frac{( x - 3 ) ^{2}}{( 6 ) ^{2}} - \frac{( y - 2 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 2), a = 6, b = 2

(\frac{x + 1}{9})^{2} - (\frac{y - 3}{16})^{2} = 1

\frac{y ^{2}}{1} - \frac{x ^{2}}{9} = 1

x^{2} - y^{2} - 8 x + 10 = 0

8 x^{2} - 2 y^{2} - 12 = 0

x^{2} - y^{2} - 16 = 0

What is ((x-3)^2)/6-((y-2)^2)/2 =1 ?
The solution to ((x-3)^2)/6-((y-2)^2)/2 =1 is Hyperbola with (h,k)=(3,2),a=sqrt(6),b=sqrt(2)