What is (y^2)/(64)-(x^2)/(16)=1 ?

The solution to (y^2)/(64)-(x^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=8,b=4

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(y^2)/(64)-(x^2)/(16)=1

\frac{y ^{2}}{64} - \frac{x ^{2}}{16} = 1

(h, k) = (0, 0), a = 8, b = 4

Solution steps

\frac{y ^{2}}{64} - \frac{x ^{2}}{16} = 1

Rewrite

\frac{y ^{2}}{64} - \frac{x ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{8 ^{2}} - \frac{( x - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 8, b = 4

\frac{( x - 4 ) ^{2}}{16} - \frac{( y + 5 ) ^{2}}{25} = 1

4 x^{2} - 3 y^{2} + 5 y - 6 y + 2 x = 7

\frac{x ^{2}}{5} - \frac{y ^{2}}{5} = 1

y^{2} - x^{2} = 121

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

What is (y^2)/(64)-(x^2)/(16)=1 ?
The solution to (y^2)/(64)-(x^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=8,b=4