What is x^2-10x-38y=-25-38 ?

The solution to x^2-10x-38y=-25-38 is Parabola with (h,k)=(5,1),p= 19/2

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x^2-10x-38y=-25-38

x^{2} - 10 x - 38 y = - 25 - 38

(h, k) = (5, 1), p = \frac{19}{2}

Solution steps

x^{2} - 10 x - 38 y = - 25 - 38

Rewrite

x^{2} - 10 x - 38 y = - 25 - 38

in the standard form

4 \cdot \frac{19}{2} (y - 1) = (x - 5)^{2}

Therefore parabola properties are:

(h, k) = (5, 1), p = \frac{19}{2}

y - 2 = (x - 3)^{2}

3 y^{2} + 48 x = 0

x^{2} = 26 y

(x - 3)^{2} = 12 (y - 4)

y^{2} \leq x

What is x^2-10x-38y=-25-38 ?
The solution to x^2-10x-38y=-25-38 is Parabola with (h,k)=(5,1),p= 19/2