What is ((x-3)^2)/(16+(y+5)^2)=1 ?

The solution to ((x-3)^2)/(16+(y+5)^2)=1 is Hyperbola with (h,k)=(3,-5),a=4,b=4

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((x-3)^2)/(16+(y+5)^2)=1

\frac{( x - 3 ) ^{2}}{16 + ( y + 5 ) ^{2}} = 1

(h, k) = (3, - 5), a = 4, b = 4

Solution steps

\frac{( x - 3 ) ^{2}}{16 + ( y + 5 ) ^{2}} = 1

Rewrite

\frac{( x - 3 ) ^{2}}{16 + ( y + 5 ) ^{2}} = 1

in the form of a standard hyperbola equation

\frac{( x - 3 ) ^{2}}{4 ^{2}} - \frac{( y - ( - 5 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, - 5), a = 4, b = 4

x^{2} - y^{2} = 71

x^{2} - y^{2} = 77

x^{2} - y^{2} = 55

x^{2} - y^{2} = 32

4 x^{2} - y^{2} + 16 x + 8 y = 36

What is ((x-3)^2)/(16+(y+5)^2)=1 ?
The solution to ((x-3)^2)/(16+(y+5)^2)=1 is Hyperbola with (h,k)=(3,-5),a=4,b=4