What is ((x-1)^2)/9-((y+3)^2)/4 =1 ?

The solution to ((x-1)^2)/9-((y+3)^2)/4 =1 is Hyperbola with (h,k)=(1,-3),a=3,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-1)^2)/9-((y+3)^2)/4 =1

\frac{( x - 1 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{4} = 1

(h, k) = (1, - 3), a = 3, b = 2

Solution steps

\frac{( x - 1 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{4} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{3 ^{2}} - \frac{( y - ( - 3 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 3), a = 3, b = 2

4 x^{2} - 18 y^{2} = 36

9 x^{2} - 4 y^{2} - 90 x + 32 y - 163 = 0

x^{2} - y^{2} = - 2

- 36 x^{2} + 64 y^{2} + 288 x + 128 y - 2816 = 0

\frac{y ^{2}}{1} - \frac{x ^{2}}{1} = 1

What is ((x-1)^2)/9-((y+3)^2)/4 =1 ?
The solution to ((x-1)^2)/9-((y+3)^2)/4 =1 is Hyperbola with (h,k)=(1,-3),a=3,b=2