What is -x^2+y^2-6=3 ?

The solution to -x^2+y^2-6=3 is Hyperbola with (h,k)=(0,0),a=3,b=3

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-x^2+y^2-6=3

- x^{2} + y^{2} - 6 = 3

(h, k) = (0, 0), a = 3, b = 3

Solution steps

- x^{2} + y^{2} - 6 = 3

Rewrite

- x^{2} + y^{2} - 6 = 3

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{3 ^{2}} - \frac{( x - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 3

x^{2} + 12 x - y^{2} + 10 y = 12

4 y^{2} - x^{2} = 4

y^{2} - 4 y = 3 x^{2} - 10 x

(\frac{a + b}{100}) \cdot (a - b) = \frac{1}{25}

x^{2} + 3 x - 2 y^{2} + y - 23 = 0

What is -x^2+y^2-6=3 ?
The solution to -x^2+y^2-6=3 is Hyperbola with (h,k)=(0,0),a=3,b=3