What is x^2-4y^2-8x+16y-36=0 ?

The solution to x^2-4y^2-8x+16y-36=0 is Hyperbola with (h,k)=(4,2),a=6,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-4y^2-8x+16y-36=0

x^{2} - 4 y^{2} - 8 x + 16 y - 36 = 0

(h, k) = (4, 2), a = 6, b = 3

Solution steps

x^{2} - 4 y^{2} - 8 x + 16 y - 36 = 0

Rewrite

x^{2} - 4 y^{2} - 8 x + 16 y - 36 = 0

in the form of a standard hyperbola equation

\frac{( x - 4 ) ^{2}}{6 ^{2}} - \frac{( y - 2 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, 2), a = 6, b = 3

2 = x^{2} - y^{2}

- 5 x^{2} + 4 y^{2} = 16

x^{2} - 4 y^{2} - 4 x - 8 y - 16 = 0

- 9 x^{2} + 25 y^{2} + 50 y - 200 = 0

4 x^{2} - 9 y^{2} - 144 = 0

What is x^2-4y^2-8x+16y-36=0 ?
The solution to x^2-4y^2-8x+16y-36=0 is Hyperbola with (h,k)=(4,2),a=6,b=3