What is (((y+4))/9)^2-(((x-3))/(25))^2=1 ?

The solution to (((y+4))/9)^2-(((x-3))/(25))^2=1 is Hyperbola with (h,k)=(3,-4),a=9,b=25

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(((y+4))/9)^2-(((x-3))/(25))^2=1

(\frac{( y + 4 )}{9})^{2} - (\frac{( x - 3 )}{25})^{2} = 1

(h, k) = (3, - 4), a = 9, b = 25

Solution steps

(\frac{y + 4}{9})^{2} - (\frac{x - 3}{25})^{2} = 1

Rewrite

(\frac{y + 4}{9})^{2} - (\frac{x - 3}{25})^{2} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 4 ) ) ^{2}}{9 ^{2}} - \frac{( x - 3 ) ^{2}}{2 5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, - 4), a = 9, b = 25

\frac{( x - 3 ) ^{2}}{25} - \frac{( y - 1 ) ^{2}}{4} = 1

\frac{x ^{2}}{7} - \frac{y ^{2}}{6} = 1

25 x^{2} - y^{2} + 50 x + 6 y - 9 = 0

\frac{( x + 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{9} = 1

x^{2} - y^{2} - 1 < 0

What is (((y+4))/9)^2-(((x-3))/(25))^2=1 ?
The solution to (((y+4))/9)^2-(((x-3))/(25))^2=1 is Hyperbola with (h,k)=(3,-4),a=9,b=25