What is ((x+4)^2)/9-((y-3)^2)/(25)=1 ?

The solution to ((x+4)^2)/9-((y-3)^2)/(25)=1 is Hyperbola with (h,k)=(-4,3),a=3,b=5

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((x+4)^2)/9-((y-3)^2)/(25)=1

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{25} = 1

(h, k) = (- 4, 3), a = 3, b = 5

Solution steps

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{25} = 1

Rewrite

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 4 ) ) ^{2}}{3 ^{2}} - \frac{( y - 3 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, 3), a = 3, b = 5

- 4 x^{2} + 25 y^{2} - 100 = 0

9 x^{2} - 7 y^{2} - 72 y + 144 = 0

4 x^{2} - 4 y^{2} + 8 x - 4 y - 3 = 0

y^{2} - 4 x^{2} - 12 y - 16 x \cdot 16 = 0

\frac{y ^{2}}{6} - 4 x^{2} = 1

What is ((x+4)^2)/9-((y-3)^2)/(25)=1 ?
The solution to ((x+4)^2)/9-((y-3)^2)/(25)=1 is Hyperbola with (h,k)=(-4,3),a=3,b=5