What is y^2+17=3x^2 ?

The solution to y^2+17=3x^2 is Hyperbola with (h,k)=(0,0),a=sqrt(17/3),b=sqrt(17)

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y^2+17=3x^2

y^{2} + 17 = 3 x^{2}

(h, k) = (0, 0), a = \frac{17}{3}, b = 17

Solution steps

y^{2} + 17 = 3 x^{2}

Rewrite

y^{2} + 17 = 3 x^{2}

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( \frac{17}{3} ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 17 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{17}{3}, b = 17

x^{2} - 2 x + 1 - y^{2} = 1

- x^{2} + y^{2} - 9 = 0

\frac{y ^{2}}{27} - \frac{x ^{2}}{9} = 1

\frac{( y - 2 ) ^{2}}{16} - \frac{( x - 1 ) ^{2}}{9} = 1

\frac{( x - 3 ) ^{2}}{16} - \frac{( y + 2 ) ^{2}}{9} = 1

What is y^2+17=3x^2 ?
The solution to y^2+17=3x^2 is Hyperbola with (h,k)=(0,0),a=sqrt(17/3),b=sqrt(17)