What is ((y-2)^2)/4-((x+3)^2)/9 =1 ?

The solution to ((y-2)^2)/4-((x+3)^2)/9 =1 is Hyperbola with (h,k)=(-3,2),a=2,b=3

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((y-2)^2)/4-((x+3)^2)/9 =1

\frac{( y - 2 ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

(h, k) = (- 3, 2), a = 2, b = 3

Solution steps

\frac{( y - 2 ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

Rewrite

\frac{( y - 2 ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( y - 2 ) ^{2}}{2 ^{2}} - \frac{( x - ( - 3 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, 2), a = 2, b = 3

y^{2} - 4 x^{2} < 1

4 x^{2} - y^{2} - 2 y = 2

[f (x)]^{2} = 4 x^{2} - x + 4

\frac{x ^{2}}{81} - \frac{y ^{2}}{144} = 1

x^{2} - y^{2} - 11 = 5

What is ((y-2)^2)/4-((x+3)^2)/9 =1 ?
The solution to ((y-2)^2)/4-((x+3)^2)/9 =1 is Hyperbola with (h,k)=(-3,2),a=2,b=3