What is (-y^2)/4+(z^2)/4 =-3/4 ?

The solution to (-y^2)/4+(z^2)/4 =-3/4 is Hyperbola with (h,k)=(0,0),a=sqrt(3)i,b=sqrt(3)

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(-y^2)/4+(z^2)/4 =-3/4

\frac{- y ^{2}}{4} + \frac{z ^{2}}{4} = - \frac{3}{4}

(h, k) = (0, 0), a = 3 i, b = 3

Solution steps

\frac{- y ^{2}}{4} + \frac{z ^{2}}{4} = - \frac{3}{4}

Rewrite

\frac{- y ^{2}}{4} + \frac{z ^{2}}{4} = - \frac{3}{4}

in the form of a standard hyperbola equation

\frac{( z - 0 ) ^{2}}{( 3 i ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3 i, b = 3

2 x^{2} - y^{2} = 17

x^{2} - 4 y^{2} = 45

a^{2} - b^{2} = 8

x^{2} - 4 y^{2} + 2 x - 8 y - 19 = 0

x^{2} - y^{2} - 8 x + 2 y + 14 = 0

What is (-y^2)/4+(z^2)/4 =-3/4 ?
The solution to (-y^2)/4+(z^2)/4 =-3/4 is Hyperbola with (h,k)=(0,0),a=sqrt(3)i,b=sqrt(3)