What is ((x+1)^2)/9-((y+2)^2)/4 =1 ?

The solution to ((x+1)^2)/9-((y+2)^2)/4 =1 is Hyperbola with (h,k)=(-1,-2),a=3,b=2

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((x+1)^2)/9-((y+2)^2)/4 =1

\frac{( x + 1 ) ^{2}}{9} - \frac{( y + 2 ) ^{2}}{4} = 1

(h, k) = (- 1, - 2), a = 3, b = 2

Solution steps

\frac{( x + 1 ) ^{2}}{9} - \frac{( y + 2 ) ^{2}}{4} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{9} - \frac{( y + 2 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{3 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, - 2), a = 3, b = 2

x^{2} - \frac{1}{3} y^{2} = x + y

x^{2} - y^{2} + 1 = 0

x, x^{2} - 48 x + 640 = m (x)^{2}

25 y^{2} - 300 y - x^{2} + 2 x + 799 = 0

\frac{x ^{2}}{36} - \frac{y ^{2}}{121} = 1

What is ((x+1)^2)/9-((y+2)^2)/4 =1 ?
The solution to ((x+1)^2)/9-((y+2)^2)/4 =1 is Hyperbola with (h,k)=(-1,-2),a=3,b=2