What is ((x-4)^2)/9-((y+7)^2)/(81)=1 ?

The solution to ((x-4)^2)/9-((y+7)^2)/(81)=1 is Hyperbola with (h,k)=(4,-7),a=3,b=9

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((x-4)^2)/9-((y+7)^2)/(81)=1

\frac{( x - 4 ) ^{2}}{9} - \frac{( y + 7 ) ^{2}}{81} = 1

(h, k) = (4, - 7), a = 3, b = 9

Solution steps

\frac{( x - 4 ) ^{2}}{9} - \frac{( y + 7 ) ^{2}}{81} = 1

Rewrite

\frac{( x - 4 ) ^{2}}{9} - \frac{( y + 7 ) ^{2}}{81} = 1

in the form of a standard hyperbola equation

\frac{( x - 4 ) ^{2}}{3 ^{2}} - \frac{( y - ( - 7 ) ) ^{2}}{9 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, - 7), a = 3, b = 9

\frac{y ^{2}}{49} - \frac{x ^{2}}{16} = 1

9 y^{2} - 7 x^{2} = 63

0 = x^{2} - y^{2} + 1

16 x^{2} - 128 x - 9 y^{2} + 36 y + 76 = 0

\frac{x ^{2}}{9} - \frac{y ^{2}}{8} = 1

What is ((x-4)^2)/9-((y+7)^2)/(81)=1 ?
The solution to ((x-4)^2)/9-((y+7)^2)/(81)=1 is Hyperbola with (h,k)=(4,-7),a=3,b=9