What is -4x^2+y^2-16x-52=0 ?

The solution to -4x^2+y^2-16x-52=0 is Hyperbola with (h,k)=(-2,0),a=6,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-4x^2+y^2-16x-52=0

- 4 x^{2} + y^{2} - 16 x - 52 = 0

(h, k) = (- 2, 0), a = 6, b = 3

Solution steps

- 4 x^{2} + y^{2} - 16 x - 52 = 0

Rewrite

- 4 x^{2} + y^{2} - 16 x - 52 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{6 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 0), a = 6, b = 3

x^{2} - y^{2} - 8 = 0

\frac{x ^{2}}{49} - \frac{y ^{2}}{81} = 1

x^{2} - 2 y^{2} - 2 x - 12 y = 35

(y + 2)^{2} - x^{2} + y = 9

3 x^{2} - 6 x - 3 y^{2} = 0

What is -4x^2+y^2-16x-52=0 ?
The solution to -4x^2+y^2-16x-52=0 is Hyperbola with (h,k)=(-2,0),a=6,b=3