What is ((y-3)^2)/9-((x-2)^2)/(16)=1 ?

The solution to ((y-3)^2)/9-((x-2)^2)/(16)=1 is Hyperbola with (h,k)=(2,3),a=3,b=4

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((y-3)^2)/9-((x-2)^2)/(16)=1

\frac{( y - 3 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

(h, k) = (2, 3), a = 3, b = 4

Solution steps

\frac{( y - 3 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

Rewrite

\frac{( y - 3 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 3 ) ^{2}}{3 ^{2}} - \frac{( x - 2 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 3), a = 3, b = 4

x^{2} - y^{2} - 4 x - 6 y = 0

(3 x - 3)^{2} - (2 y - 4)^{2} = 68

64 x^{2} - 100 y^{2} = 6400

\frac{x ^{2}}{49} - \frac{y ^{2}}{4} = 1

\frac{( y - 3 ) ^{2}}{16} - \frac{( x + 4 ) ^{2}}{25} = 1

What is ((y-3)^2)/9-((x-2)^2)/(16)=1 ?
The solution to ((y-3)^2)/9-((x-2)^2)/(16)=1 is Hyperbola with (h,k)=(2,3),a=3,b=4