What is y^2=4x^2+(-2) ?

The solution to y^2=4x^2+(-2) is Hyperbola with (h,k)=(0,0),a=sqrt(1/2),b=sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^2=4x^2+(-2)

y^{2} = 4 x^{2} + (- 2)

(h, k) = (0, 0), a = \frac{1}{2}, b = 2

Solution steps

y^{2} = 4 x^{2} - 2

Rewrite

y^{2} = 4 x^{2} - 2

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( \frac{1}{2} ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{1}{2}, b = 2

\frac{x ^{2}}{4} - \frac{y ^{2}}{9} = 4

4 x^{2} + 24 x - 9 y^{2} + 54 y - 81 = 0

4 x^{2} - 2 y^{2} - 4 = 0

y^{2} - 4 x^{2} - 16 x - 2 y - 19 = 0

9 x^{2} - 16 y^{2} + 144 = 0

What is y^2=4x^2+(-2) ?
The solution to y^2=4x^2+(-2) is Hyperbola with (h,k)=(0,0),a=sqrt(1/2),b=sqrt(2)