What is ((y-6)^2)/(36)-((x+1)^2)/(16)=1 ?

The solution to ((y-6)^2)/(36)-((x+1)^2)/(16)=1 is Hyperbola with (h,k)=(-1,6),a=6,b=4

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((y-6)^2)/(36)-((x+1)^2)/(16)=1

\frac{( y - 6 ) ^{2}}{36} - \frac{( x + 1 ) ^{2}}{16} = 1

(h, k) = (- 1, 6), a = 6, b = 4

Solution steps

\frac{( y - 6 ) ^{2}}{36} - \frac{( x + 1 ) ^{2}}{16} = 1

Rewrite

\frac{( y - 6 ) ^{2}}{36} - \frac{( x + 1 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 6 ) ^{2}}{6 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 6), a = 6, b = 4

x^{2} - y^{2} = 2^{100}

x^{2} - y^{2} + x - y - 44 = 0

4 x^{2} - 25 y^{2} + 24 x + 100 y + 36 = 0

16 x^{2} - 4 y^{2} = 49

16 x^{2} - 9 y^{2} - 36 y = 108

What is ((y-6)^2)/(36)-((x+1)^2)/(16)=1 ?
The solution to ((y-6)^2)/(36)-((x+1)^2)/(16)=1 is Hyperbola with (h,k)=(-1,6),a=6,b=4