What is ((y-2)^2)/9-((x+1)^2)/4 =1 ?

The solution to ((y-2)^2)/9-((x+1)^2)/4 =1 is Hyperbola with (h,k)=(-1,2),a=3,b=2

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((y-2)^2)/9-((x+1)^2)/4 =1

\frac{( y - 2 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{4} = 1

(h, k) = (- 1, 2), a = 3, b = 2

Solution steps

\frac{( y - 2 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{4} = 1

Rewrite

\frac{( y - 2 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( y - 2 ) ^{2}}{3 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 2), a = 3, b = 2

\frac{( y - 3 ) ^{2}}{49} - \frac{( x + 2 ) ^{2}}{16} = 1

y^{2} \leq x^{2} + y

36 y^{2} = 4 x^{2} + 144

y^{2} - 9 = x^{2}

3 y^{2} - 12 x^{2} - 36 y - 48 x + 48 = 0

What is ((y-2)^2)/9-((x+1)^2)/4 =1 ?
The solution to ((y-2)^2)/9-((x+1)^2)/4 =1 is Hyperbola with (h,k)=(-1,2),a=3,b=2