What is ((y+7)^2)/4-((x+2)^2)/(16)=1 ?

The solution to ((y+7)^2)/4-((x+2)^2)/(16)=1 is Hyperbola with (h,k)=(-2,-7),a=2,b=4

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((y+7)^2)/4-((x+2)^2)/(16)=1

\frac{( y + 7 ) ^{2}}{4} - \frac{( x + 2 ) ^{2}}{16} = 1

(h, k) = (- 2, - 7), a = 2, b = 4

Solution steps

\frac{( y + 7 ) ^{2}}{4} - \frac{( x + 2 ) ^{2}}{16} = 1

Rewrite

\frac{( y + 7 ) ^{2}}{4} - \frac{( x + 2 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 7 ) ) ^{2}}{2 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, - 7), a = 2, b = 4

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{9} = 1

(\frac{y}{2})^{2} - 2 y = \frac{3}{2} x^{2} - 5 x

x^{2} - 4 y^{2} + 6 x + 24 y - 40 = 0

\frac{( y - 1 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{16} = 1

x^{2} - 9 y^{2} = 27

What is ((y+7)^2)/4-((x+2)^2)/(16)=1 ?
The solution to ((y+7)^2)/4-((x+2)^2)/(16)=1 is Hyperbola with (h,k)=(-2,-7),a=2,b=4