What is ((x-1)^2)/3-(y^2)/4 =1 ?

The solution to ((x-1)^2)/3-(y^2)/4 =1 is Hyperbola with (h,k)=(1,0),a=sqrt(3),b=2

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((x-1)^2)/3-(y^2)/4 =1

\frac{( x - 1 ) ^{2}}{3} - \frac{y ^{2}}{4} = 1

(h, k) = (1, 0), a = 3, b = 2

Solution steps

\frac{( x - 1 ) ^{2}}{3} - \frac{y ^{2}}{4} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{3} - \frac{y ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{( 3 ) ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 0), a = 3, b = 2

x^{2} - y^{2} - 64 = 0

y^{2} - 4 x^{2} - 4 y - 8 x - 4 = 0

1 = \frac{( y - 1 ) ^{2}}{2} - \frac{x ^{2}}{2}

x^{2} - y^{2} + 8 y - 12 = 0

4 x^{2} - 5 y^{2} = 20

What is ((x-1)^2)/3-(y^2)/4 =1 ?
The solution to ((x-1)^2)/3-(y^2)/4 =1 is Hyperbola with (h,k)=(1,0),a=sqrt(3),b=2