What is ((2y-3x}{18})(\frac{2y+3x)/2)=1 ?

The solution to ((2y-3x}{18})(\frac{2y+3x)/2)=1 is Hyperbola with (h,k)=(0,0),a=3,b=2

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((2y-3x}{18})(\frac{2y+3x)/2)=1

(\frac{2 y - 3 x}{18}) (\frac{2 y + 3 x}{2}) = 1

(h, k) = (0, 0), a = 3, b = 2

Solution steps

\frac{2 y - 3 x}{18} \cdot \frac{2 y + 3 x}{2} = 1

Rewrite

\frac{2 y - 3 x}{18} \frac{2 y + 3 x}{2} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{3 ^{2}} - \frac{( x - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 2

x^{2} - 2 y^{2} = 7

x^{2} - 2 y^{2} = 2

4 y^{2} - 9 x^{2} + 40 y - 540 x - 8036 = 0

16 x^{2} - 25 y^{2} - 400 = 0

x^{2} - 25 y^{2} - 14 x + 100 y - 76 = 0

What is ((2y-3x}{18})(\frac{2y+3x)/2)=1 ?
The solution to ((2y-3x}{18})(\frac{2y+3x)/2)=1 is Hyperbola with (h,k)=(0,0),a=3,b=2