What is (x-y-3)*(x+y+3)=16 ?

The solution to (x-y-3)*(x+y+3)=16 is Hyperbola with (h,k)=(0,-3),a=4,b=4

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(x-y-3)*(x+y+3)=16

(x - y - 3) \cdot (x + y + 3) = 16

(h, k) = (0, - 3), a = 4, b = 4

Solution steps

(x - y - 3) (x + y + 3) = 16

Rewrite

(x - y - 3) (x + y + 3) = 16

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - ( - 3 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 3), a = 4, b = 4

y^{2} - 3 y - 2 = x^{2}

\frac{( x + 1 ) ^{2}}{2} - \frac{( y - 2 ) ^{2}}{1} = 1

\frac{y ^{2}}{4} - \frac{x ^{2}}{25} = 1

x^{2} - y^{2} = - \frac{3}{8}

9 x^{2} - 4 y^{2} - 36 x - 24 y = 36

What is (x-y-3)*(x+y+3)=16 ?
The solution to (x-y-3)*(x+y+3)=16 is Hyperbola with (h,k)=(0,-3),a=4,b=4