What is ((y+3)^2)/9-((x-2)^2)/(16)=1 ?

The solution to ((y+3)^2)/9-((x-2)^2)/(16)=1 is Hyperbola with (h,k)=(2,-3),a=3,b=4

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((y+3)^2)/9-((x-2)^2)/(16)=1

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

(h, k) = (2, - 3), a = 3, b = 4

Solution steps

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

Rewrite

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 3 ) ) ^{2}}{3 ^{2}} - \frac{( x - 2 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, - 3), a = 3, b = 4

- 9 = x^{2} - y^{2}

2 x^{2} - 5 y^{2} = 52

- 4 x^{2} + y^{2} + 20 x + 10 y - 25 = 0

\frac{9 y ^{2}}{36} - \frac{4 x ^{2}}{36} = 1

\frac{x ^{2}}{3} - \frac{y ^{2}}{5} = 1

What is ((y+3)^2)/9-((x-2)^2)/(16)=1 ?
The solution to ((y+3)^2)/9-((x-2)^2)/(16)=1 is Hyperbola with (h,k)=(2,-3),a=3,b=4