What is -2x^2+y^2-4=0 ?

The solution to -2x^2+y^2-4=0 is Hyperbola with (h,k)=(0,0),a=2,b=sqrt(2)

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-2x^2+y^2-4=0

- 2 x^{2} + y^{2} - 4 = 0

(h, k) = (0, 0), a = 2, b = 2

Solution steps

- 2 x^{2} + y^{2} - 4 = 0

Rewrite

- 2 x^{2} + y^{2} - 4 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{2 ^{2}} - \frac{( x - 0 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 2

3 x^{2} - y^{2} + 30 x + 8 y = - 71

4 x^{2} - 4 y^{2} + 28 x - 8 y + 53 = 0

\frac{( x - 2 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{9} = 1

9 x^{2} - 4 y^{2} - 72 x + 16 y + 92 = 0

\frac{( y + 4 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

What is -2x^2+y^2-4=0 ?
The solution to -2x^2+y^2-4=0 is Hyperbola with (h,k)=(0,0),a=2,b=sqrt(2)