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Popular >

t^2=27+u^2

Solution

t^{2} = 27 + u^{2}

Solution

(h, k) = (0, 0), a = 33, b = 33

Solution steps

t^{2} = 27 + u^{2}

Rewrite

t^{2} = 27 + u^{2}

in the form of a standard hyperbola equation

\frac{( t - 0 ) ^{2}}{( 3 3 ) ^{2}} - \frac{( u - 0 ) ^{2}}{( 3 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 33, b = 33

Popular Examples

(x^2}{81}-\frac{y^2)/4 =1

\frac{x ^{2}}{81} - \frac{y ^{2}}{4} = 1

(x^2)/9+(8x)/9-(y^2)/9+(8y)/9-1/81 =0

\frac{x ^{2}}{9} + \frac{8 x}{9} - \frac{y ^{2}}{9} + \frac{8 y}{9} - \frac{1}{81} = 0

x^{2} - y^{2} + 2 > 0

3 x^{2} - 2 y^{2} = 30

3 x^{2} - 2 y^{2} = 36

Frequently Asked Questions (FAQ)

What is t^2=27+u^2 ?
The solution to t^2=27+u^2 is Hyperbola with (h,k)=(0,0),a=3sqrt(3),b=3sqrt(3)