What is 4x^2-y^2-24x-4y+16=0 ?

The solution to 4x^2-y^2-24x-4y+16=0 is Hyperbola with (h,k)=(3,-2),a=2,b=4

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4x^2-y^2-24x-4y+16=0

4 x^{2} - y^{2} - 24 x - 4 y + 16 = 0

(h, k) = (3, - 2), a = 2, b = 4

Solution steps

4 x^{2} - y^{2} - 24 x - 4 y + 16 = 0

Rewrite

4 x^{2} - y^{2} - 24 x - 4 y + 16 = 0

in the form of a standard hyperbola equation

\frac{( x - 3 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, - 2), a = 2, b = 4

\frac{( y - 1 ) ^{2}}{49} - \frac{( x - 2 ) ^{2}}{32} = 1

4 x^{2} + 8 x - 3 y^{2} + 16 = 0

f (x) (f (x)) = x^{2} + 1

y^{2} - 2 y - (x^{2} - x - 1) = 0

4 x^{2} + 4 y^{2} - 9 + 18 y - 9 x^{2} = 0

What is 4x^2-y^2-24x-4y+16=0 ?
The solution to 4x^2-y^2-24x-4y+16=0 is Hyperbola with (h,k)=(3,-2),a=2,b=4