What is ((x-1)^2)/4-((y+2)^2)/4 =1 ?

The solution to ((x-1)^2)/4-((y+2)^2)/4 =1 is Hyperbola with (h,k)=(1,-2),a=2,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-1)^2)/4-((y+2)^2)/4 =1

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{4} = 1

(h, k) = (1, - 2), a = 2, b = 2

Solution steps

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{4} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 2, b = 2

\frac{( x - 6 ) ^{2}}{25} - (y + 1)^{2} = 1

\frac{( y - 6 ) ^{2}}{9} - (x - 6)^{2} = 1

\frac{( x + 2 ) ^{2}}{16} - \frac{y ^{2}}{9} = 1

\frac{( x - 2 ) ^{2}}{16} - \frac{( y + 3 ) ^{2}}{1} = 1

(- \frac{p}{( 2 - q )}) (- \frac{( p - 1 )}{q}) = - 1

What is ((x-1)^2)/4-((y+2)^2)/4 =1 ?
The solution to ((x-1)^2)/4-((y+2)^2)/4 =1 is Hyperbola with (h,k)=(1,-2),a=2,b=2