What is a^2+150=b^2+9 ?

The solution to a^2+150=b^2+9 is Hyperbola with (h,k)=(0,0),a=sqrt(141),b=sqrt(141)

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a^2+150=b^2+9

a^{2} + 150 = b^{2} + 9

(h, k) = (0, 0), a = 141, b = 141

Solution steps

a^{2} + 150 = b^{2} + 9

Rewrite

a^{2} + 150 - b^{2} - 9 = 0

in the form of a standard hyperbola equation

\frac{( b - 0 ) ^{2}}{( 141 ) ^{2}} - \frac{( a - 0 ) ^{2}}{( 141 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 141, b = 141

3 x^{2} - 5 y^{2} = 7

\frac{( x - 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{5} = 1

6 x^{(2)} - 5 y^{(2)} + 24 x + 20 y - 56 = 0

\frac{x ^{2}}{49} - \frac{( y + 2 ) ^{2}}{79} = 1

- \frac{x ^{2}}{144} + \frac{y ^{2}}{25} = 1

What is a^2+150=b^2+9 ?
The solution to a^2+150=b^2+9 is Hyperbola with (h,k)=(0,0),a=sqrt(141),b=sqrt(141)