What is ((x+4)^2)/4-((y-5)^2)/(45)=1 ?

The solution to ((x+4)^2)/4-((y-5)^2)/(45)=1 is Hyperbola with (h,k)=(-4,5),a=2,b=3sqrt(5)

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((x+4)^2)/4-((y-5)^2)/(45)=1

\frac{( x + 4 ) ^{2}}{4} - \frac{( y - 5 ) ^{2}}{45} = 1

(h, k) = (- 4, 5), a = 2, b = 35

Solution steps

\frac{( x + 4 ) ^{2}}{4} - \frac{( y - 5 ) ^{2}}{45} = 1

Rewrite

\frac{( x + 4 ) ^{2}}{4} - \frac{( y - 5 ) ^{2}}{45} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 4 ) ) ^{2}}{2 ^{2}} - \frac{( y - 5 ) ^{2}}{( 3 5 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, 5), a = 2, b = 35

\frac{- x ^{2}}{36} + \frac{y ^{2}}{16} = 1

\frac{a ^{2} - 4 b ^{2} - 15}{π} = 0

x^{2} - 1 y^{2} = 13

- 9 x^{2} + 36 x + 4 y^{2} - 24 y = 63

3 x^{2} - 4 y^{2} + 3 - 6 x + 16 y - 18 = 0

What is ((x+4)^2)/4-((y-5)^2)/(45)=1 ?
The solution to ((x+4)^2)/4-((y-5)^2)/(45)=1 is Hyperbola with (h,k)=(-4,5),a=2,b=3sqrt(5)