What is (x^2)/(64)-(y^2)/(49)=1 ?

The solution to (x^2)/(64)-(y^2)/(49)=1 is Hyperbola with (h,k)=(0,0),a=8,b=7

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(x^2)/(64)-(y^2)/(49)=1

\frac{x ^{2}}{64} - \frac{y ^{2}}{49} = 1

(h, k) = (0, 0), a = 8, b = 7

Solution steps

\frac{x ^{2}}{64} - \frac{y ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{64} - \frac{y ^{2}}{49} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{8 ^{2}} - \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 8, b = 7

\frac{x ^{2}}{3} - \frac{y ^{2}}{8} = 1

(x + 3)^{2} - y^{2} = 159

y^{2} - 2 x^{2} + 4 x - 4 y = 0

9 x^{(2)} - 36 x - 16 y^{(2)} - 32 y = 124

y = (x^{2} - y^{2})

What is (x^2)/(64)-(y^2)/(49)=1 ?
The solution to (x^2)/(64)-(y^2)/(49)=1 is Hyperbola with (h,k)=(0,0),a=8,b=7