What is ((y+2)^2)/4-((x+3)^2)/9 =1 ?

The solution to ((y+2)^2)/4-((x+3)^2)/9 =1 is Hyperbola with (h,k)=(-3,-2),a=2,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y+2)^2)/4-((x+3)^2)/9 =1

\frac{( y + 2 ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

(h, k) = (- 3, - 2), a = 2, b = 3

Solution steps

\frac{( y + 2 ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

Rewrite

\frac{( y + 2 ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{2 ^{2}} - \frac{( x - ( - 3 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, - 2), a = 2, b = 3

x, r (x)^{2} = (x - 0.5)^{2} + (x + 0.5)^{2}

25 (x - 3)^{2} - 5 (y - 1)^{2} = 125

π (a^{2} - b^{2}) = \frac{49 π}{2}

a^{2} - b^{2} = 891

\frac{( x + 2 ) ^{2}}{10} - \frac{( y + 4 ) ^{2}}{25} = 1

What is ((y+2)^2)/4-((x+3)^2)/9 =1 ?
The solution to ((y+2)^2)/4-((x+3)^2)/9 =1 is Hyperbola with (h,k)=(-3,-2),a=2,b=3