What is ((x-0)^2)/((2)^2)-((y-k)^2)/((2)^2)=1 ?

The solution to ((x-0)^2)/((2)^2)-((y-k)^2)/((2)^2)=1 is Hyperbola with (h,k)=(0,k),a=2,b=2

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((x-0)^2)/((2)^2)-((y-k)^2)/((2)^2)=1

\frac{( x - 0 ) ^{2}}{( 2 ) ^{2}} - \frac{( y - k ) ^{2}}{( 2 ) ^{2}} = 1

(h, k) = (0, k), a = 2, b = 2

Solution steps

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - k ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, k), a = 2, b = 2

3 y^{2} - x^{2} + 24 y - 2 x = 0

x^{2} - y^{2} = 60

x^{2} - y^{2} = 67

5 x^{2} - y^{2} \geq 13

5 x^{2} - y^{2} \geq 11

What is ((x-0)^2)/((2)^2)-((y-k)^2)/((2)^2)=1 ?
The solution to ((x-0)^2)/((2)^2)-((y-k)^2)/((2)^2)=1 is Hyperbola with (h,k)=(0,k),a=2,b=2