What is (x^2)/(16)-(y^2)/(81)=1 ?

The solution to (x^2)/(16)-(y^2)/(81)=1 is Hyperbola with (h,k)=(0,0),a=4,b=9

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(x^2)/(16)-(y^2)/(81)=1

\frac{x ^{2}}{16} - \frac{y ^{2}}{81} = 1

(h, k) = (0, 0), a = 4, b = 9

Solution steps

\frac{x ^{2}}{16} - \frac{y ^{2}}{81} = 1

Rewrite

\frac{x ^{2}}{16} - \frac{y ^{2}}{81} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{9 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 9

x^{2} - 9 y^{2} + 8 x + 36 y - 29 = 0

7 y^{2} - 12 x^{2} = 84

x^{2} - y^{2} = \frac{1}{2}

y^{2} - (\frac{x ^{2}}{64}) = 1

x^{2} - y^{2} = 50

What is (x^2)/(16)-(y^2)/(81)=1 ?
The solution to (x^2)/(16)-(y^2)/(81)=1 is Hyperbola with (h,k)=(0,0),a=4,b=9