What is ((x-1)^2}{49}-\frac{(y+3)^2)/9 =1 ?

The solution to ((x-1)^2}{49}-\frac{(y+3)^2)/9 =1 is Hyperbola with (h,k)=(1,-3),a=7,b=3

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((x-1)^2}{49}-\frac{(y+3)^2)/9 =1

\frac{( x - 1 ) ^{2}}{49} - \frac{( y + 3 ) ^{2}}{9} = 1

(h, k) = (1, - 3), a = 7, b = 3

Solution steps

\frac{( x - 1 ) ^{2}}{49} - \frac{( y + 3 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{49} - \frac{( y + 3 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{7 ^{2}} - \frac{( y - ( - 3 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 3), a = 7, b = 3

(y - 3) (y + 1) - (2 x + 1) (x - 3) = 0

x^{2} - 3 y^{2} + 6 y + 6 = 0

9 y^{2} - 16 x^{2} + 18 y + 64 x - 199 = 0

- 8 x^{2} + y^{2} - 32 x - 16 y = - 16

\frac{1}{2} y^{2} = 2 x^{2} - 0.02

What is ((x-1)^2}{49}-\frac{(y+3)^2)/9 =1 ?
The solution to ((x-1)^2}{49}-\frac{(y+3)^2)/9 =1 is Hyperbola with (h,k)=(1,-3),a=7,b=3