What is ((y+2)^2)/9-((x+2)^2)/4 =1 ?

The solution to ((y+2)^2)/9-((x+2)^2)/4 =1 is Hyperbola with (h,k)=(-2,-2),a=3,b=2

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((y+2)^2)/9-((x+2)^2)/4 =1

\frac{( y + 2 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

(h, k) = (- 2, - 2), a = 3, b = 2

Solution steps

\frac{( y + 2 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

Rewrite

\frac{( y + 2 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{3 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, - 2), a = 3, b = 2

18 x^{2} - 9 y^{2} - 96 x - 36 y - 36 = 0

\frac{x ^{2}}{14} - \frac{y ^{2}}{20} = 1

y^{2} - 2 x^{2} - 16 = 0

x^{2} = 280 0^{2} + y^{2} - 2 (2800) (y) cos (2 0^{\circ})

x^{2} - (y - 3960)^{2} = 396 0^{2}

What is ((y+2)^2)/9-((x+2)^2)/4 =1 ?
The solution to ((y+2)^2)/9-((x+2)^2)/4 =1 is Hyperbola with (h,k)=(-2,-2),a=3,b=2