What is 3x^2-4y^2+y=9(2.1) ?

The solution to 3x^2-4y^2+y=9(2.1) is Hyperbola with (h,k)=(0, 1/8),a=2.50582…,b=2.17010…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3x^2-4y^2+y=9(2.1)

3 x^{2} - 4 y^{2} + y = 9 (2.1)

(h, k) = (0, \frac{1}{8}), a = 2.50582 \dots, b = 2.17010 \dots

Solution steps

3 x^{2} - 4 y^{2} + y = 9 \cdot 2.1

Rewrite

3 x^{2} - 4 y^{2} + y = 92.1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2.50582 \dots ^{2}} - \frac{( y - \frac{1}{8} ) ^{2}}{2.17010 \dots ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, \frac{1}{8}), a = 2.50582 \dots, b = 2.17010 \dots

x^{2} - 4 y^{2} + 2 x - 1 y - 4 = 0

x^{2} + 11 = y^{2} + 6 x - 2 y

4 x^{2} - 8 y^{2} + 6 x + 12 y - 82 = 0

x^{2} - y^{2} - 3 x + 4 y = 0

(x - y) (x + y + 6) = - 9

What is 3x^2-4y^2+y=9(2.1) ?
The solution to 3x^2-4y^2+y=9(2.1) is Hyperbola with (h,k)=(0, 1/8),a=2.50582…,b=2.17010…