What is ((x-1)^2)/4-((y+2)^2)/9 =1 ?

The solution to ((x-1)^2)/4-((y+2)^2)/9 =1 is Hyperbola with (h,k)=(1,-2),a=2,b=3

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((x-1)^2)/4-((y+2)^2)/9 =1

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{9} = 1

(h, k) = (1, - 2), a = 2, b = 3

Solution steps

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 2, b = 3

25 x^{2} - 36 y^{2} - 200 x + 360 y - 1400 = 0

25 y^{2} - 9 x^{2} + 18 x - 50 y = 241

\frac{y ^{2}}{4} - \frac{x ^{2}}{6} = 1

- 4 x^{2} + y^{2} + 10 y - 11 = 0

\frac{- x ^{2}}{16} + \frac{y ^{2}}{36} = 1

What is ((x-1)^2)/4-((y+2)^2)/9 =1 ?
The solution to ((x-1)^2)/4-((y+2)^2)/9 =1 is Hyperbola with (h,k)=(1,-2),a=2,b=3