What is ((y^2}{16})-(\frac{x^2)/4)=1 ?

The solution to ((y^2}{16})-(\frac{x^2)/4)=1 is Hyperbola with (h,k)=(0,0),a=4,b=2

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((y^2}{16})-(\frac{x^2)/4)=1

(\frac{y ^{2}}{16}) - (\frac{x ^{2}}{4}) = 1

(h, k) = (0, 0), a = 4, b = 2

Solution steps

\frac{y ^{2}}{16} - \frac{x ^{2}}{4} = 1

Rewrite

\frac{y ^{2}}{16} - \frac{x ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{4 ^{2}} - \frac{( x - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 2

3 x^{2} - y^{2} - 2 x - 4 = 0

27 x^{2} - 36 y^{2} - 216 x - 72 y + 225 = 0

a = a^{2} - b^{2}

\frac{x ^{2}}{8} - \frac{y ^{2}}{64} = 1

2 x 4 x + (- 2) y 4 y = - 200

What is ((y^2}{16})-(\frac{x^2)/4)=1 ?
The solution to ((y^2}{16})-(\frac{x^2)/4)=1 is Hyperbola with (h,k)=(0,0),a=4,b=2