What is y^1y=(x+2)(x-1) ?

The solution to y^1y=(x+2)(x-1) is Hyperbola with (h,k)=(-1/2 ,0),a= 3/2 ,b= 3/2

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y^1y=(x+2)(x-1)

y^{1} y = (x + 2) (x - 1)

(h, k) = (- \frac{1}{2}, 0), a = \frac{3}{2}, b = \frac{3}{2}

Solution steps

y^{1} y = (x + 2) (x - 1)

Rewrite

y^{1} y - (x + 2) (x - 1) = 0

in the form of a standard hyperbola equation

\frac{( x - ( - \frac{1}{2} ) ) ^{2}}{( \frac{3}{2} ) ^{2}} - \frac{( y - 0 ) ^{2}}{( \frac{3}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- \frac{1}{2}, 0), a = \frac{3}{2}, b = \frac{3}{2}

3 (x - 1)^{2} = 6 + 2 (y + 1)^{2}

(x - 5)^{2} - (y - 4)^{2} = 25

x^{2} - 3 y^{2} = 4

x^{2} - y^{2} = - 7

x^{2} - y^{2} = - 8

What is y^1y=(x+2)(x-1) ?
The solution to y^1y=(x+2)(x-1) is Hyperbola with (h,k)=(-1/2 ,0),a= 3/2 ,b= 3/2