What is (x-3)(x+1)=yy ?

The solution to (x-3)(x+1)=yy is Hyperbola with (h,k)=(1,0),a=2,b=2

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(x-3)(x+1)=yy

(x - 3) (x + 1) = yy

(h, k) = (1, 0), a = 2, b = 2

Solution steps

(x - 3) (x + 1) = yy

Rewrite

(x - 3) (x + 1) - yy = 0

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 0), a = 2, b = 2

x^{2} - 25 y^{2} = 25

x^{2} + 6 x - 4 y^{2} - 8 y + 9 = 0

y^{2} = 3 6^{2} + x^{2}

\frac{( x - 1 ) ^{2}}{4} - (y - 1)^{2} = 1

x + 2 y (y - x) = 2 x^{2} - 2 x y - x^{2}

What is (x-3)(x+1)=yy ?
The solution to (x-3)(x+1)=yy is Hyperbola with (h,k)=(1,0),a=2,b=2