What is ((x-3)^2)/1-((y-2)^2)/3 =1 ?

The solution to ((x-3)^2)/1-((y-2)^2)/3 =1 is Hyperbola with (h,k)=(3,2),a=1,b=sqrt(3)

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((x-3)^2)/1-((y-2)^2)/3 =1

\frac{( x - 3 ) ^{2}}{1} - \frac{( y - 2 ) ^{2}}{3} = 1

(h, k) = (3, 2), a = 1, b = 3

Solution steps

\frac{( x - 3 ) ^{2}}{1} - \frac{( y - 2 ) ^{2}}{3} = 1

Rewrite

\frac{( x - 3 ) ^{2}}{1} - \frac{( y - 2 ) ^{2}}{3} = 1

in the form of a standard hyperbola equation

\frac{( x - 3 ) ^{2}}{1 ^{2}} - \frac{( y - 2 ) ^{2}}{( 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 2), a = 1, b = 3

\frac{( y + 3 ) ^{2}}{( 64 )} - \frac{( x - 2 ) ^{(2)}}{( 84 )} = 1

5 x^{2} - 4 y^{2} - 20 x + 8 y - 4 = 0

\frac{( y - 1 ) ^{2}}{25} - \frac{( x + 2 ) ^{2}}{9} = 1

25 x^{2} - 4 y^{2} - 100 x - 16 y - 16 = 0

x^{2} - 5 y^{2} = 25

What is ((x-3)^2)/1-((y-2)^2)/3 =1 ?
The solution to ((x-3)^2)/1-((y-2)^2)/3 =1 is Hyperbola with (h,k)=(3,2),a=1,b=sqrt(3)