What is ((y-8)^2)/(25)-((x-12)^2)/(16)=1 ?

The solution to ((y-8)^2)/(25)-((x-12)^2)/(16)=1 is Hyperbola with (h,k)=(12,8),a=5,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y-8)^2)/(25)-((x-12)^2)/(16)=1

\frac{( y - 8 ) ^{2}}{25} - \frac{( x - 12 ) ^{2}}{16} = 1

(h, k) = (12, 8), a = 5, b = 4

Solution steps

\frac{( y - 8 ) ^{2}}{25} - \frac{( x - 12 ) ^{2}}{16} = 1

Rewrite

\frac{( y - 8 ) ^{2}}{25} - \frac{( x - 12 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 8 ) ^{2}}{5 ^{2}} - \frac{( x - 12 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (12, 8), a = 5, b = 4

(a - b) (a + b) = 3000

y^{2} = x^{2} + 576

3 4^{2} + x^{2} = y^{2}

y^{(2)} - 9 x^{2} + 8 x - 8 y - 2 = 0

x^{2} - y^{2} = 225

What is ((y-8)^2)/(25)-((x-12)^2)/(16)=1 ?
The solution to ((y-8)^2)/(25)-((x-12)^2)/(16)=1 is Hyperbola with (h,k)=(12,8),a=5,b=4