What is -((x-3)/2)^2+((y-2)/5)^2=1 ?

The solution to -((x-3)/2)^2+((y-2)/5)^2=1 is Hyperbola with (h,k)=(3,2),a=5,b=2

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-((x-3)/2)^2+((y-2)/5)^2=1

- (\frac{x - 3}{2})^{2} + (\frac{y - 2}{5})^{2} = 1

(h, k) = (3, 2), a = 5, b = 2

Solution steps

- (\frac{x - 3}{2})^{2} + (\frac{y - 2}{5})^{2} = 1

Rewrite

- (\frac{x - 3}{2})^{2} + (\frac{y - 2}{5})^{2} = 1

in the form of a standard hyperbola equation

\frac{( y - 2 ) ^{2}}{5 ^{2}} - \frac{( x - 3 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 2), a = 5, b = 2

x^{2} - y^{2} = 2^{2}

x^{2} - 6 x - 9 y^{2} - 54 y - 81 = 0

\frac{( x - 4 ) ^{2}}{9} - \frac{( y - 4 ) ^{2}}{4} = 1

9 x^{2} - 4 y^{2} + 90 x + 189 = 0

3 x^{2} - y^{2} + 7 x - y + 18 = 0

What is -((x-3)/2)^2+((y-2)/5)^2=1 ?
The solution to -((x-3)/2)^2+((y-2)/5)^2=1 is Hyperbola with (h,k)=(3,2),a=5,b=2