What is ((x-5)^2)/9-((y-4)^2)/(25)=1 ?

The solution to ((x-5)^2)/9-((y-4)^2)/(25)=1 is Hyperbola with (h,k)=(5,4),a=3,b=5

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((x-5)^2)/9-((y-4)^2)/(25)=1

\frac{( x - 5 ) ^{2}}{9} - \frac{( y - 4 ) ^{2}}{25} = 1

(h, k) = (5, 4), a = 3, b = 5

Solution steps

\frac{( x - 5 ) ^{2}}{9} - \frac{( y - 4 ) ^{2}}{25} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{9} - \frac{( y - 4 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - 5 ) ^{2}}{3 ^{2}} - \frac{( y - 4 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, 4), a = 3, b = 5

x, h (x)^{2} = (5)^{2} + (12)^{2} + (x)^{2}

4 x^{2} - y^{2} - 20 x - 10 y - 25 = 0

18 x^{2} - 32 y^{2} - 108 y - 128 x - 254 = 0^{2}

\frac{x ^{2}}{5} - \frac{y ^{2}}{1} = 1

3 y^{2} - x^{2} + 18 y + 4 x + 28 = 0

What is ((x-5)^2)/9-((y-4)^2)/(25)=1 ?
The solution to ((x-5)^2)/9-((y-4)^2)/(25)=1 is Hyperbola with (h,k)=(5,4),a=3,b=5