What is y^2=x^2+2x-15 ?

The solution to y^2=x^2+2x-15 is Hyperbola with (h,k)=(-1,0),a=4,b=4

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y^2=x^2+2x-15

y^{2} = x^{2} + 2 x - 15

(h, k) = (- 1, 0), a = 4, b = 4

Solution steps

y^{2} = x^{2} + 2 x - 15

Rewrite

y^{2} = x^{2} + 2 x - 15

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 0), a = 4, b = 4

x^{2} - y^{2} - 2 = 0

9 y^{2} - 4 x^{2} - 36 = 0

6 (x + \frac{1}{3})^{2} - 6 (y - \frac{1}{2})^{2} + 24 = 0

(y)^{2} + (5)^{2} = (6 + 2 + x)^{2}

y^{2} - 9 x^{2} - 6 y - 18 x - 9 = 0

What is y^2=x^2+2x-15 ?
The solution to y^2=x^2+2x-15 is Hyperbola with (h,k)=(-1,0),a=4,b=4