What is (y-4)^2-((x+1)^2)/(16)=1 ?

The solution to (y-4)^2-((x+1)^2)/(16)=1 is Hyperbola with (h,k)=(-1,4),a=1,b=4

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(y-4)^2-((x+1)^2)/(16)=1

(y - 4)^{2} - \frac{( x + 1 ) ^{2}}{16} = 1

(h, k) = (- 1, 4), a = 1, b = 4

Solution steps

(y - 4)^{2} - \frac{( x + 1 ) ^{2}}{16} = 1

Rewrite

(y - 4)^{2} - \frac{( x + 1 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 4 ) ^{2}}{1 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 4), a = 1, b = 4

144 y^{2} - 25 x^{2} = 3600

x^{2} - 25 y^{2} - 4 x + 75 y - 27 = 0

36 x^{2} - 4 y^{2} = 144

\frac{y ^{2}}{36} - \frac{x ^{2}}{49} = 1

\frac{( x + 2 ) ^{2}}{64} - \frac{( y - 3 ) ^{2}}{36} = 1

What is (y-4)^2-((x+1)^2)/(16)=1 ?
The solution to (y-4)^2-((x+1)^2)/(16)=1 is Hyperbola with (h,k)=(-1,4),a=1,b=4