What is ((x-9)^2)/9-((y+4)^2)/(25)=1 ?

The solution to ((x-9)^2)/9-((y+4)^2)/(25)=1 is Hyperbola with (h,k)=(9,-4),a=3,b=5

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((x-9)^2)/9-((y+4)^2)/(25)=1

\frac{( x - 9 ) ^{2}}{9} - \frac{( y + 4 ) ^{2}}{25} = 1

(h, k) = (9, - 4), a = 3, b = 5

Solution steps

\frac{( x - 9 ) ^{2}}{9} - \frac{( y + 4 ) ^{2}}{25} = 1

Rewrite

\frac{( x - 9 ) ^{2}}{9} - \frac{( y + 4 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - 9 ) ^{2}}{3 ^{2}} - \frac{( y - ( - 4 ) ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (9, - 4), a = 3, b = 5

(a - b) (a + b) = 2 (3 a - 6)

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{20 0 ^{2}} = 1

9 x^{2} - 4 y^{2} + 18 x + 32 y = 119

3 x^{2} - 3 y^{2} + 30 x - 6 y + 25 = 0

\frac{( x - 7 ) ^{2}}{a ^{2}} - \frac{( y + 6 ) ^{2}}{b ^{2}} = 1

What is ((x-9)^2)/9-((y+4)^2)/(25)=1 ?
The solution to ((x-9)^2)/9-((y+4)^2)/(25)=1 is Hyperbola with (h,k)=(9,-4),a=3,b=5